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Half-sandwich complexes of titanium and zirconium with the (diisopropylaminoethyl)cyclopentadienyl ligand - Molecular structure of [((C5H4CH2CH2NCH)(i)Pr-2)ZnCl3](+)Cl-.2CH(3)OH

Author

Listed:
  • Jutzi, Peter

    (Center for Mathematical Economics, Bielefeld University)

  • Redeker, T

    (Center for Mathematical Economics, Bielefeld University)

  • Neumann, B

    (Center for Mathematical Economics, Bielefeld University)

  • Stammler, Hans-Georg

    (Center for Mathematical Economics, Bielefeld University)

Abstract

The synthesis of titanium and zirconium complexes with the donor functionalized 2-(N,N-diisopropylaminoethyl)cyclopentadienyl (CpN) ligand is described. The reaction of TiCl4 with ((C5H4CH2CH2NPr2)-Pr-i)Li leads to the formation of the highly moisture-sensitive half-sandwich complex ((C5H4CH2CH2NPr2)-Pr-1)TiCl3 (1), which easily forms a coordination polymer. Complex 1 reacts with one equivalent of HCl under protonation of the amino group to give the monomeric hydrochloride [(C5H4CH2CH2N(H)Pr-i(2))TiCl3]Cl-+(-) (2), which shows excellent solubility in polar solvents. The compound ((C5H4CH2CH2NPr2)-Pr-i)Ti(NMe2)(3) (3) is prepared by the reaction of Ti(NMe,), with one equivalent of (C5H5CH2CH2NPr2)-Pr-i ((CpH)-H-N). Reaction of 3 with three equivalents of isopropanol affords the isopropoxy derivative ((C5H4CH2CH2NPr2)-Pr-i)Ti((OPr)-Pr-i), (4) in quantitative yield. The reaction of ((C5H4CH2C2NPr2)-Pr-i)Li with Me3SiCl leads to the formation of the Cp-N-transfer reagent ((C5H4CH2CN2NPr2)-Pr-i)SiMe3 (5). The polymeric zirconium compound [((C5H4CH2CH2NPr2)-Pr-i)ZrCl3](x) (6) is synthesized by the reaction of 5 with ZrCl4. 6 reacts with one equivalent of HCl under protonation of the amino group to give the monomeric air- and moisture-stable hydrochloride [(C5H4CH2CH2N(H)Pr-i(2))ZrCl3]Cl-+(-).2CH(2)OH (7). The structure of 7 has been determined by single-crystal X-ray diffractometry. The reaction of 7 with water leads under exchange of the donor ligands to the formation of the air- and water-stable hydrochloride [(C5H4CH2CH2N(H)Pr-i(2))ZrCl3]Cl-+(-).2H(2)O (8). The compound ((C5H4CH2CH2NPr2)-Pr-i)Zr(NMe2)(3) (9) is prepared by the reaction of Zr(NMe2)(4) with one equivalent of (C5H5CH2CH2NPr2)-Pr-i in nearly quantitative yield.

Suggested Citation

  • Jutzi, Peter & Redeker, T & Neumann, B & Stammler, Hans-Georg, 2010. "Half-sandwich complexes of titanium and zirconium with the (diisopropylaminoethyl)cyclopentadienyl ligand - Molecular structure of [((C5H4CH2CH2NCH)(i)Pr-2)ZnCl3](+)Cl-.2CH(3)OH," Center for Mathematical Economics Working Papers 533, Center for Mathematical Economics, Bielefeld University.
  • Handle: RePEc:bie:wpaper:533
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    References listed on IDEAS

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    Keywords

    (diisopropylaminoethyl)cyclopentadienyl ligand; titanium; zirconium; half-sandwich;

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