Is a subspace containing a splitting subspace a splitting subspace?
If V, A and B are three closed subspaces of we say that V is a splitting subspace for A,B if and only if A and B are conditionally orthogonal given V. If V is a splitting subspace for A,B, we shall say that V splits A,B. Rozanov [Rozanov,Â Y.A., 1979. Stochastic Markovian Fields. In: Developments in Statistics, vol.Â 2. Academic Press, New York, p.Â 205] observes that A[perpendicular]BV does not imply that the closed subspace W[superset of or equal to]V splits A,B. However, no example is provided. In this note we provide one.
Volume (Year): 78 (2008)
Issue (Month): 17 (December)
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References listed on IDEAS
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- Lutkepohl, Helmut, 1982. "Non-causality due to omitted variables," Journal of Econometrics, Elsevier, vol. 19(2-3), pages 367-378, August.
- Granger, C. W. J., 1980. "Testing for causality : A personal viewpoint," Journal of Economic Dynamics and Control, Elsevier, vol. 2(1), pages 329-352, May.
- Granger, C W J, 1969. "Investigating Causal Relations by Econometric Models and Cross-Spectral Methods," Econometrica, Econometric Society, vol. 37(3), pages 424-38, July.
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